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3 years ago

What is the value of x

Mathematics

2 answers:

liraira [26]3 years ago

8 0

180 - 100 = 80

x + 70 + 80 = 180

x + 150 = 180

x = 30

Answer

B. 30

Orlov [11]3 years ago

4 0

Hey!

The sum of all 3 angles in a triangle always adds up to 180°. One of the angles is 70°. Another angle is 80° because 180 - 100 = 80. Add the 2 angles and subtract it from 180.

$70 + 80 = 150$

The sum of the 2 angles is 150°. Subtract that from 180

$180 - 150 = 30$

That means x is equal to 30

$\framebox{Answer = 30 \° = B}$ .

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(5x – 3) a 1170 -b please help

ArbitrLikvidat [17]

Answer: x= 114/5

Step-by-step explanation:

Opposite angles in between parallel lines are equal. Just solve for x. (5x-3)=117

6 0

2 years ago

4. Given the points M(-3, -4) and T(5,0), find the coordinates of the point Q on directed line segment MT that partitions MT in

Firlakuza [10]

Answer:

4 :  Coordinate of Q = $(\frac{1}{5} ,\frac{-12}{5} )$

5 : Coordinate of point A = (-2,-2)

Explanation :

4) Given the points M(-3, -4) and T(5,0)

x₁= -3, y₁ = -4 and

x₂ = 5, y₂ = 0

m = 2, n = 1

Now apply the section formula,

{(mx₂+nx₁)/(m+n) , (my₂+ny₁)/(m+n)}

Coordinate of point Q = $(\frac{1}{5} ,\frac{-12}{5} )$

5) AB:BC = 3:4

A = (x,y), end point

B = (4, 1)

C = (12, 5) end point

So, m = 3 & n = 4

x₁ = x , y₁ = y , x₂=12 & y₂ = 5

Apply section formula we get

4 = (36+4x)/7 & 1 = (15 + 4y)/7

28= 36 + 4x 7 = 4y + 15

4x =-8 4y =-8

x = -2 y = -2

5 0

3 years ago

56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(

PIT_PIT [208]

There are 2 tangent lines that pass through the point

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

Explanation:

Given:

$y=\frac{x}{x+1}$

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

$y=m(x-1)+2$ $[1]$

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for $m$ :

$\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\$

$\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}$

$\frac{dy}{dx}= \frac{1}{(x+1)^2}$

$m=\frac{1}{(x+1)^2}$ $[2]$

Substitute equation [2] into equation [1]:

$y=\frac{x-1}{(x+1)^2}+2$ $[1.1]$

Because the line must touch the curve, we may substitute $y=\frac{x}{x+1}:$

$\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2$

Solve for x:

$x(x+1)=(x-1)+2(x+1)^2$

$x^2+x=x-1+2x^2+4x+2$

$x^2+4x+1$

$x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}$

$x=-2$ ± $\sqrt{3}$

$x=-2$ ± $\sqrt{3}$ $and$ $x=-2-\sqrt{3}$

There are 2 tangent lines.

$y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2$

and

$y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2$

8 0

2 years ago

If 7x - 4y = 23 and x + y = 8, what is the value of x?

Margaret [11]

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x = 55

Divide each side by 11

11x/11 = 55/11

x = 5

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Hoochie [10]

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