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3 years ago

P^2+2p-63=0 solve by completing the square

Mathematics

1 answer:

algol [13]3 years ago

7 0

Step-by-step explanation:

p^2+2p=63

p^2+2p+1^2=63+1^2

p^2+2p+1=64

(p+1)^2=64

p+1=8

p=8-1

p=7

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IRINA_888 [86]

Answer:

Part A: hx2=a

Part B: 5hours

Step-by-step explanation:

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3 years ago

Use function notation to represent the area of a circle whose circumference is 103 cm

Nataly_w [17]

Circumference of the circle $=103$ cm

i.e., $C = 2 \pi r = 103$

i.e., $r = \frac{103}{2 \pi}$

Area of the circle is given by

$A = \pi r^2$

$A = \pi (\frac{103}{2 \pi})^2$

$A = \pi (\frac{10609}{4 \pi^2})$

$A =\frac{10609}{4 \pi}$

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3 years ago

What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-

Irina18 [472]

The sum of the infinite geometric series is -288.

<h2>Given that</h2>

A finite geometric series with n = 4, a₁ = -144, and r = ½.

<h3>We have to determine</h3>

What is the sum of the infinite geometric series?

<h3>According to the question</h3>

The sum of the infinite is determined by the following formula;

$\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\$

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

$\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\S\infty = \dfrac{-144 (1- \dfrac{1}{2}^4)}{1-\dfrac{1}{2}}\\\\S \infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\S \infty = -270$

Therefore,

The sum of the infinite geometric series is,

$\rm S = \dfrac{a_1}{1-r}\\\\S=\dfrac{-144}{1-\dfrac{1}{2}}\\\\S = \dfrac{-144}{0.5}\\\\S = -288$

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

brainly.com/question/16037289

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3 years ago

Y=-x^2+4<br> y=2x+1<br> I'm not sure how to solve for this system of equations

balu736 [363]

Do you need x as your answer or y

4 0

3 years ago

Using the formula y=mx+b whats the equation of (2,-8) with a slope of -1?

Leona [35]

Answer:

y = -x - 6

Step-by-step explanation:

Given:

slope = -1
point (2,-8)

From:

$\displaystyle \large{y=mx+b}$

where m = slope and b = y-intercept. Therefore:

$\displaystyle \large{y=-1x+b}\\\displaystyle \large{y=-x+b}$

Since the equation passes through a point (2,-8). Substitute x = 2 and y = -8 in and solve for b:

$\displaystyle \large{-8=-2+b}\\\displaystyle \large{-8+2=b}\\\displaystyle \large{b=-6}$

Then substitute b-value in the equation:

$\displaystyle \large{y=-x+b}\\\displaystyle \large{\therefore y=-x-6}$

Hence, the equation is y = -x - 6

4 0

2 years ago

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