The best thing to do is to find what 1% is, and you can do this by dividing 150 by 100.
150/100= 1.5
As you're looking for 6.5%, you've got to multiply 1.5 by 6.5
1.5*6.5= 9.75
You've then got to add 9.75 and 150 together
150+9.75= $159.75
Therefore, after the sales tax, the cost of the necklace is $159.75
Hope this helps :)
<u>Corrected question :</u>
Solve the equation. Write your answer as an integer or simplified fraction.
<u>Required Solution :</u>
The given equation,
★ Multiplying -7 into (n - 2),
>> 8n - 7 × (n - 2) = 18
>> 8n - 7n + 14 = 18
★ On substracting 7n from 8n we gets,
>> n + 14 = 18
★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),
>> n = 18 - 14
>> n = 14
★ Therefore,
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Answer:
The answer is
Step-by-step explanation:
❃Incase you forgot what the linear equation formula is ↶
❃Since we already have the slope, we don't need to solve for that.
➊ First: We are going to find the y-intercept.
➋Second: Plug in.
Answer:
1/6
Step-by-step explanation:
this is because when u divide the numerator and denominator by 5 you get 1/6
<span>If there has to be 2 men and 2 women, we know
that we must take a group of 2 men out of the group of 15 men and a group of 2
women out of the group of 20 women. Therefore, we have:
(15 choose 2) x (20 choose 2)
(15 choose 2) = 105
(20 choose 2) = 190
190*105 = 19950
Therefore, there are 19950 ways to have a group of 4 with 2 men and 2women.</span>
<span>If there has to be 1 man and 3 women, we know
that we must take a group of 1 man out of the group of 15 men and a group of 3
women out of the group of 20 women. Therefore, we have:
(15 choose 1) x (20 choose 3)
(15 choose 1) = 15
(20 choose 3) = 1140
15*1140 = 17100
Therefore, there are 17100 ways to have a group of 4 with 3 women and 1 man.</span>
<span>We now find the total outcomes of having a group
with 4 women.
We know this is the same as saying (20 choose 4) = 4845</span>
Therefore, there are 4845 ways to have a group of
4 with 4 women.
We now add the outcomes of 2 women, 3 women, and
4 women and get the total ways that a committee can have at least 2 women.
19950 + 17100 + 4845 = 41895 ways that there will
be at least 2 women in the committee
