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3 years ago

18. 11² + c² = 15² a.±104 b. ±6.1 c. ±10.2 d. ±2

Mathematics

1 answer:

lianna [129]3 years ago

4 0

C. Po
Sorry po kung mali

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3 years ago

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Suppose the weekly revenue for a company is given byr: 202400p wherep is the price of their product. What is the price of their

Rudiy27

Answer:

(a) The price for a revenue of $18,750 is $239.2.

(b) They sold 710 colonial houses and 2130 ranch houses

Step-by-step explanation:

(a) If the weekly revenue is defined as

$r=2p^2+400p$

then the price must be calculated as:

$r=2p^2+400p=18750\\\\2p^2+400p-18750=0$

The roots of this function are

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-400 \pm \sqrt{400^2-4*2*(-18750)}}{2*2}\\ \\x=\frac{-400 \pm 556.78}{4}\\ \\x_1=-39.2\\x_2=239.2$

The first root is negative, so it is not a real solution. So the second root is the answer.

The price for a revenue of $18,750 is $239.2.

(b) Last year they sold three times as many ranch models (Hr) as they did colonial models (Hc):

$H_r=3*H_c$

The total amount of houses sold (colonial + ranch) is 2840

$H_c+H_r=2840\\H_c+3*H_c=2840\\4*H_c=2840\\H_c=2840/4=710\\\\H_r = 3*H_c=3*710=2130$

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3 years ago

18. 11² + c² = 15² a.±104 b. ±6.1 c. ±10.2 d. ±2​

18. 11² + c² = 15² a.±104 b. ±6.1 c. ±10.2 d. ±2