A major factor in how the periodic table<span> is organized is the configuration of each </span>element's<span> valence electrons. Because </span>elements<span> in each family have the same number of valence electrons, they tend to have several similar </span>characteristics<span>.</span>
Answer:
c = λ f
c is the speed of light, λ the wavelength in meters, and f equals the frequency in cycles per second.
Explanation:
<h3>Further explanation</h3>
Given
Reaction
H₂ (g) + I₂ (g) → 2HI(g)
Required
The equilibrium constant
Solution
The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient
The equilibrium constant for reaction
pA + qB ⇒ mC + nD
![\large {\boxed {\bold {K ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BK%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
So for the above reaction :
![\tt K=\dfrac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=%5Ctt%20K%3D%5Cdfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
Answer:
Explanation:
Nitrogen is use to store semen for artificial insemination because if it's inert characteristics which it help to maintain the semen inertness and also it maintain the low temperature of the semen which is good for it's quality.
Nitrogen also help to prevent it's biological deterioration thereby maintaining it's viability and effectiveness.
Answer:
This metal could be lead
Specific heat = 0.0308 cal/g°C
Explanation:
Step 1: Data given
The metal was heated to 115.0°C
in a calorimeter where it cooled to 32.6°C.
Mass of the metal = 25.0 grams
Heat released = 63.5 cal
Step 2: Calculate the specific heat of the metal
Q = m*c*ΔT
⇒with Q = the heat released = 63.5 cal
⇒with m = the mass of the metal = 25.0 grams
⇒with ΔT = the change of temperature = T2 - T1 = 32.6 °C - 115.0°C = -82.4 °C
⇒ c = the specific heat = TO BE DETERMINED
63.5 = 25.0 * c * 82.4
C = 0.0308 cal/g°C
This metal could be lead