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zloy xaker [14]
2 years ago
14

A motorcyclist completes a journey at an average speed of 65 mph

Chemistry
1 answer:
Andrews [41]2 years ago
8 0
227.5

Hope this helps :)
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A chemist reacts 30.0 mL of 5.6 M HCl with an excess of Mg(OH)2 How many grams of magnesium will be produced
Mkey [24]

Answer:

2.042 g

Explanation:

The reaction that takes place is:

  • 2HCl + Mg(OH)₂ → Mg²⁺ + 2Cl⁻ + 2H₂O

First we <u>calculate how many HCl moles were added</u>, using <em>the given volume and concentration</em>:

  • 30 mL ⇒ 30 / 1000 = 0.030 L
  • 5.6 M * 0.030 L = 0.168 mol HCl

Then we<u> convert HCl moles into Mg²⁺ moles</u>, using the<em> stoichiometric coefficients</em>:

  • 0.168 mol HCl * \frac{1molMg^{+2}}{2molHCl}= 0.084 mol Mg⁺²

Finally we <u>convert Mg moles into grams</u>, using its<em> molar mass</em>:

  • 0.084 mol Mg⁺² * 24.305 g/mol = 2.042 g
3 0
3 years ago
According to the enthalpy diagram below, which of the following statements is true?
stich3 [128]

Answer:it will be c on edg 2021

Explanation:

7 0
3 years ago
Read 2 more answers
Water at 25 °C flows at 5 ft/s through a straight cylindrical tube made of benzoic acid, with a 1-inch inside diameter. If the t
defon

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

8 0
3 years ago
QUESTION THREE
BartSMP [9]

Answer:

Odds to be given for an event that either Romance or Downhill wins is 11:4

Explanation:

Given an odd, r = a : b. The probability of the odd, r can be determined by;

     Pr(r) = \frac{a}{b} ÷ (

So that;

Odd that Romance will win = 2:3

Pr(R) = \frac{2}{3} ÷ (

        = \frac{2}{3} ÷ \frac{5}{3}

       = \frac{2}{5}

Odd that Downhill will win = 1:2

Pr(D) = \frac{1}{2} ÷ (

        =  \frac{1}{2} ÷ \frac{3}{2}

        = \frac{1}{3}

The probability that either Romance or Downhill will win is;

Pr(R) + Pr(D) = \frac{2}{5} +  \frac{1}{3}

                    = \frac{11}{15}

The probability that neither Romance nor Downhill will win is;

Pr(neither R nor D) = (1 - \frac{11}{15})

                               = \frac{4}{15}

The odds to be given for an event that either Romance or Downhill wins can be determined by;

                               = Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)

                               = \frac{11}{15} ÷ \frac{4}{15}

                              = \frac{11}{4}

Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4

8 0
2 years ago
Given the following reaction:
Wewaii [24]

Answer:

Approx. 4⋅g.

Explanation:

Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.

Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.

Given the stoichiometry,

mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.

Why did I multiply the mass in this equation by 2? Am I pulling your leg?

3 0
2 years ago
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