Question

The radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-g sample of radon- (3 222 would be left after approximately 23 days?​

Answer 1

Answer:

1.115 g

Explanation:

Applying,

R = R'$2^{n/t}$................... Equation 1

Where R = original sample of radon-222, R' = sample of radon-222 left after decay, n = Total time, t = half-life.

make R' the subject of the equation

R' = R/($2^{n/t}$)............... Equation 2

From the question,

Given: R = 73.9 g, n = 23 days, t = 3.8 days.

Substitute these values into equation 2

R' = 73.9/($2^{23/3.8}$)

R' = 73.9/$2^{6.05}$

R' = 1.115 g