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Yuki888 [10]
3 years ago
15

PLEASE HELP ME I JUST NEED THIS QUESTION PLEASE ANYONE

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:Since x-intercepts just where the line touches the x-axis, you only need to find the coordinate of that point, which is (8,0) in (x,y) coordinate format.

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(3)/(2x+3)=(2)/(10x+4) Solve the proportion.
PtichkaEL [24]

Answer:

x = -3/13

Step-by-step explanation:

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

--> Thus the equation becomes:

3 ⋅  (10x+4) = (2x+3) ⋅  2

--> Simplify

30x + 12 = 4x + 6

--> Combine Like Terms

26x + 12 = 6

26x = -6

--> Divide each term and simplify

x = -3/13

Hope this helps!

5 0
3 years ago
- Round each number to four decimal places: a. 5.16 b. 5.27​
DochEvi [55]

Answer:

wym by 4 decimal places

Step-by-step explanation:

5 0
3 years ago
What is 40% of $2.20... 
padilas [110]
100% ............. 2.20
40%   .............   x 
-----------------------------

x=40*2.20/100
x=88 / 100
x= 0.88

The answer is x=0.88
6 0
4 years ago
Read 2 more answers
how do you get the answer for 1 5 over 8 and decimal 1.625 PLZ HELP I WILL GIVE YOU 50 POINTS FOR THIS
frutty [35]
1.625 as a fraction is 1 5/8

15/8 simplified is 1 7/8

if you are using the word "and" to represent multiplication here you go:

first i would change both fractions to a mixed number

13/8×15/8=195/64
simplify

your answer would be 3 3/64

if you are using "and" to represent adding here you go:

1.625 as a fraction is 1 5/8

first i would change 1 5/8 to a mixed number:  13/8

so then add 15/8+13/8=28/8

simplify:  
28÷4=7
8÷4=2

7/2=3 1/2
  
i hope this helped
7 0
3 years ago
The upper class limit of a class is
Oliga [24]

Answer:

C. the largest value of that class

Step-by-step explanation:

Class limit is like an interval it has the lowest value and largest value and the all values between these lower and upper values lie within that class.

Hence, the Upper Class limit of a class is the largest value of that class.

Thus, only option C is correct.

7 0
3 years ago
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