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nignag [31]
3 years ago
12

What is the remainder of f(x)=x^4-2x^3-27x^2-9x+18 when divided by binomial x+4

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

The remainder will be 6.

Step-by-step explanation:

We have the function:

f(x)=x^4-2x^3-27x^2-9x+18

And we want to find the remainder after it is divided by the binomial:

x+4

We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (<em>x</em> - <em>a</em>), then the remainder will be given by P(a).

Here, our divisor is (<em>x</em> + 4). We can rewrite this as (<em>x</em> - (-4)).

Therefore, <em>a</em> = -4.

Then according to the PRT, the remainder will be:

f(-4)=(-4)^4-2(-4)^3-27(-4)^2-9(-4)+18=6

The remainder will be 6.

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Bond [772]

Answer:

peanut butter cookies:8

sugar cookies:2

chocolate chip cookies:5

ratio: 4:1:2.5

Step-by-step explanation:

x=peanut butter cookies

y=sugar cookies

a=chocolate chip cookies

40=2x+3y+3.6a

15=x+y+a

x=a+3

15=(a+3)+y+a

y=12-2a

40=2(a+3)+3(12-2a)+3.6a

a=5

x=8

y=2

5 0
3 years ago
et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe
Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation f(x)=x+\lvert 2x-3 \rvert=12 can be solved as follows:

x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}

\lvert 2x-3 \rvert =12-x

2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)

3x=15\,\,\text{or}\,\,\x=-9

Then, the solutions of the equation are x=5, x=-9.

Now, if g(x)=5x-3+\lvert x+4\rvert, we can solve the equation g(a)=4a+9 as follows:

5a-3+\lvert a+4 \rvert =4a+9

\lvert a+4\rvert =4a+9-5a+3

a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)

2a=8\,\,\text{or}\,\,4=12

So, the unique solution of this last equation is a=4

The last equation is h(x-1)=x-3, where h(x)=\lvert x \rvert -2x+5.. To solve this equation we can proceed as follows:

h(x-1)=x-3

\lvert x-1\rvert -2(x-1)+5=x-3

\lvert x-1 \rvert -2x+2+5=x-3

\lvert x-1\rvert =3x-10

x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)

-2x=-9\,\,\text{or}\,\,4x=11

x=9/2\,\,\text{or}\,\,x=11/4

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

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