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Elis [28]
4 years ago
15

A 250 mL beaker can hold 0.192 kg of acetone. What is the density of this substance, in g/mL? Round your answer to 3 significant

digits.
Mathematics
1 answer:
Andreyy894 years ago
3 0
Density = m/v with mass being in grams and volume in mL......
192 grams/250 mL = 0.768 g/mL
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Which of the following points is not coplanar with polnis C, D and E?
Leokris [45]

Answer: Point R

===================================================

Explanation:

The term "coplanar" means "points that are in the same plane".

Points A, S and U are all in the base plane. Think of this as the floor of the pyramid, so to speak. These three points are with C, D, and E, which are also on the base plane or floor plane. So we can say that all of these points are coplanar.

In contrast, point R is not on the floor plane. It's higher up. So that's why R is not coplanar with points C,D,E.

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3 years ago
B) Here are the first four terms of a quadratic sequence.
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Find answer is the given attachment

5 0
3 years ago
Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
today at Allison's cupcake and cookie budget for her party at $105 if you would like to have at least 40 cupcakes and cookies co
Sati [7]

Answer:

a  ≤  b  +  5

a  +  b  ≥  40  

2.5 a  +  1.5 b  ≤  105

Step-by-step explanation:

3 0
3 years ago
Let g(x)=9x−10 and evaluate g(x+h)−g(x)/h
castortr0y [4]

Answer:

\frac{g(x+h)-g(x)}{h}=9

Step-by-step explanation:

we have

g(x)=9x-10

To find out g(x+h) substitute the variable x by the variable (x+h) in the function g(x)

so

g(x+h)=9(x+h)-10

g(x+h)=9x+9h-10

Evaluate

\frac{g(x+h)-g(x)}{h}

we have

g(x+h)=9x+9h-10

g(x)=9x-10

substitute in the expression

\frac{9x+9h-10-(9x-10)}{h}

\frac{9x+9h-10-9x+10)}{h}

\frac{9h}{h}

9

therefore

\frac{g(x+h)-g(x)}{h}=9

3 0
3 years ago
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