9514 1404 393
Answer:
3433 m^2
Step-by-step explanation:
The total surface area is the sum of the end areas and the lateral area.
The end areas together are a circle of diameter 0.4 m and two rectangles that are 0.4 m by 0.55 m.
End areas = πr^2 + 2LW = 3.14(0.2 m)^2 + 2(0.4 m)(0.55 m)
= 0.1256 m^2 +0.44 m^2 = 0.5656 m^2
The perimeter of the end piece is half the circumference of a 0.4 m circle and three sides of a 0.4 m by 0.55 m rectangle.
P = (1/2)πd + 2L +W = 1/2·3.14·0.4 m + 2(0.55 m) + 0.4 m = 2.128 m
The lateral area of the mailbox is the product of its length and the perimeter of the end piece:
LA = PL = (2.128 m)(0.6 m) = 1.2768 m^2
Then the total surface area of the mailbox is ...
0.5656 m^2 + 1.2768 m^2 = 1.8424 m^2
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The area of aluminum required for 1863 mailboxes is ...
1863 × 1.8424 m^2 ≈ 3433 m^2
About 3433 square meters of aluminum are needed to make these mailboxes.
Answer:
170x+240y<2000
Step-by-step explanation:
sunrise- 170x
twilight- 240y
both of them added together has to equal/ be less than 2000
since i can't do the less than or equal to sign you will have to pretend there is a line under the < sign
<
_
Answer:
(x−7)(x+5)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x−7=0x+5=0
Set the first factor equal to 0 and solve.
x=7
Set the next factor equal to 0 and solve.
x=−5
The final solution is all the values that make (x−7(x+5)=0 true. x={7,−5}
Answer:
i don't what you want me to do here...
You gave me the same problem just two different numbers so maybe the answer is 7... idek tho bro
k times x = 7
k times x = 49
Step-by-step explanation:
