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dimulka [17.4K]
3 years ago
12

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). 3 to the power

6/5
The expression above can also be written in the form c√a^b.
For this expression, a = , b = , and c =
.
Mathematics
1 answer:
Andreas93 [3]3 years ago
8 0

Answer:

For this expression, a = 3, b = 6, and c = 5.

Step-by-step explanation:

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The number of donuts produced by a machine is directly proportional to the time the machine runs . The machine produces 380 donu
mrs_skeptik [129]

Answer:

855 donuts

Step-by-step explanation:

380/20 = 19 donuts per minute

19 × 45 = 855

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3 years ago
Value of sin^-1(sin 9pi/7)
mrs_skeptik [129]
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sin^{-1}[sin(whatever)]= whatever\\\\
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tan^{-1}[tan(whatever)]= whatever
\end{array}\\\\
------------------\\\\
\begin{array}{llll}
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3 0
3 years ago
Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
The number 6458 rounded to the nearest thousand
Murrr4er [49]

Answer:

6500

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi
pishuonlain [190]

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

108/4       <   (4W + 0)/4

       27     <    W              

      the width has to be greater than 27 meters

   

5 0
3 years ago
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