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jenyasd209 [6]
3 years ago
6

A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi

dth
Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

108/4       <   (4W + 0)/4

       27     <    W              

      the width has to be greater than 27 meters

   

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