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Flura [38]
3 years ago
12

Find the equation of this line

Mathematics
1 answer:
Anna71 [15]3 years ago
8 0

Answer:

y = x+6

Step-by-step explanation:

You can see that (0,6) and (1,7) are points on the line, and the y-intercept of the line is 6.

Use the coordinates of these points to find the slope of the line.

slope = (7-6)/(1-0) = 1

y-intercept = 6

Slope-intercept equation for line of slope 1  that has y-intercept of 6:

y = x+6

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Find the area of the triangle formed by the origin and the points of intersection of parabolas y=− 1/3 (x−1)^2+8 and y=x^2−2x−3.
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Answer:

The area of the triangle formed by origin, and the points (4,5) and (-2,5) will be 15 sq. units.

Step-by-step explanation:

The two parabolas are y = - \frac{1}{3}(x - 1)^{2} + 8 and y = x² - 2x - 3.

Now, solving those two equations we will get the points of intersection.

So, - \frac{1}{3}(x - 1)^{2} + 8 = x^{2} - 2x - 3

⇒ - (x - 1)² + 24 = 3x² - 6x - 9

⇒ -x² + 2x - 1 + 24 = 3x² - 6x - 9

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⇒ x² - 2x - 8 = 0

⇒ x² - 4x + 2x - 8 = 0

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So, x = 4 or - 2.

Now, for x = 4 , y = 4² - 2(4) - 3 = 5 and the point of intersection is (4,5).

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Now, points (4,5) and (-2,5) make a straight line parallel to the x-axis at a perpendicular distance of 5 units from origin and its length is (4 - (- 2)) = 6 units.

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3 years ago
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