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Debora [2.8K]
2 years ago
5

Which angles are supplementary?

Mathematics
1 answer:
professor190 [17]2 years ago
8 0

Answer:

c 2,3

Step-by-step explanation:

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Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height
GrogVix [38]

The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

y = a(x - h)^2 + k

where  (h,k)  is the vertex of the  parabola and here it is (5 , 16.5), so we have the function:-

y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



7 0
3 years ago
Read 2 more answers
Brian bought a new air conditioning unit on his credit card. The unit had a base price of $435. Brian made no other purchases on
Svetlanka [38]

Answer:

D is the correct answer

Step-by-step explanation:

Given:

Unit base price: $435

Credit Card interest rate, i = 9.4% compounded monthly; i = 0.00783/month comp monthly

n = 1.5 years = 18 months

sales tax = 8.51%

First, determine the actual price of the unit by adding the sales tax to the base price of the unit:

$435 * (1 + 0.0851)

Actual price = $472.0185

So, the total amount paid by Brian should be higher than the actual price since he used his credit card. Use the formula from economics:

F = P (1+i)^n

F = $507.96

Therefore, the total amount paid by Brian is $507.96.

(Hope this helps can I pls have brainlist (crown) ☺️)

3 0
2 years ago
Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
Your insurance premium is $3400 annually. Your employer pays 80% of the premium. How much will you pay annually?
pochemuha
I think it is 680 if not i am sorry
4 0
3 years ago
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The two data sets show random samples of the costs, in dollars, of cars purchased at two dealerships yesterday.
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7 0
3 years ago
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