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Svetlanka [38]
2 years ago
12

Hellp iv been trying for daysssssss

Mathematics
1 answer:
Shkiper50 [21]2 years ago
5 0

Answer:

There are mathematics you could purchase that has answer sheets, what grade you in?

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(1.7x10^4) x (8.5x10^-2)
iogann1982 [59]

Step-by-step explanation:

(1.7x10^4) x (8.5x10^-2)

17000 × 0.085

= 1445

6 0
3 years ago
Use a table of values to estimate the value of the limit. Confirm your result graphically by graphing the function with a graphi
il63 [147K]
Hello,

\lim_{x \to 0}\dfrac{ \sqrt{x+25}-5}{x}\\\\

=\lim_{x \to 0}\dfrac{(\sqrt{x+25}-5)*(\sqrt{x+25}+5)}{x*(\sqrt{x+25}+5)}\\\\

=\lim_{x \to 0}\dfrac{x+25-25)}{x*(\sqrt{x+25}+5)}\\\\


=\dfrac{1}{10}

















4 0
3 years ago
How do I do this I need help right now
kodGreya [7K]
To answer this (specifically the first one) you have to count how many spaces each point moves. (How many spaces up/down does it go? Left/right?) then you put rise (up/down) over run (left/right) and you should get the slope!
6 0
2 years ago
A movie streaming website charges an initial fee of $80, plus $4 for each movie that is streamed. How many movies must be stream
pochemuha

Answer:

80 movies must be streamed.

Step-by-step explanation:

To find the average cost, you must divide the total cost by the number of movies watched.

When you watch 1 movie, you pay the initial fee of $80 plus a $4 purchase of the film.

The equation is shown as such:

average cost = (total cost)/(number of movies)

Your total cost can be represented as 4x + 80, while the number of movies is represented as x.

You want the average to equal 5, so your equation is shown as follows:

5 = (4x+80)/x

simplifying this, we get

5 = 4 + \frac{80}{x}

which can then be simplified to

1 = \frac{80}{x}

X = 80 movies.

4 0
2 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
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