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Svetlanka [38]
2 years ago
5

How to write 0.12 repeating as a fractiom

Mathematics
1 answer:
frosja888 [35]2 years ago
5 0

Answer:

4/33

Step-by-step explanation:

do the normal steps to conversion

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If a rectangle has length x and width x-2, what is the perimeter of the rectangle in terms of x?​
ivolga24 [154]

Answer:

length x and width x-2

perimeter of rectangle=2[l+b]=2[(x-2)+x]=4x-4 is your answer

6 0
3 years ago
Determine the range with symbols, will give Brainlist if correct
Ostrovityanka [42]
(-4,6)
Jendbdjxidndjeidjd
6 0
3 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
=-2\pi

So, the flux over the paraboloid alone is

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
3 years ago
How many different groups of 35 cars can be formed from 40 cars?
snow_tiger [21]
658,008 i just looked it up and thats what i found.
7 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP! REALLY IMPORTANT! MUST BE CORRECT! POINTS GIVEN!
VMariaS [17]
 - 5/12  +  ( - 1/4) = 

Adding two negatives results in a negative

-1/4 = -3/12

-3/12 + -5/12  =  -8/12

-8/12 + 3/12    < Subtract and take the sign of the BIGGER number.

8 - 3 = 5

- 5/12

Answer:  - 5/12
8 0
2 years ago
Read 2 more answers
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