Answer:
Its A.
Step-by-step explanation:
Edge 2021
If e is between them, then the distances DE and EF add to the total, DF. So the answer is just 27 + 34 which is 61, A
If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
A, B, C, E
Step-by-step explanation:
It can be seen from the figure that the points A, B, C and D, all are lying in the line t.
=> So that it can be concluded that AC and BC and BD have the slopes which are equal to each other and also equal to the slop of line t
So that all answer A, B, C are true.
In addition, as FD is parallel with x - axis, so that slope of the line t is equal to <em>tan angel FDB </em>
As FDB is the right triangle with BFD = 90°
=> tan angel FDB = FB/ FD (tan of an acute angel in the right triangle = opposite side/ adjacent side)
=> Slope of the line t is equal to FB/ FD
=> Answer E is true