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3 years ago

14

Need ASAP answer because I don’t not understand

2 answers:

dimaraw [331]3 years ago

6 0

Hello there! The correct answer is B.

Note that in functions, x values cannot repeat. The points are given as (x, y) values, and you can see in the second option there are two -7s in the x values, making it not a function!

<em>I hope this was helpful, have a great rest of your day! If you need further help with this question, let me know!</em>

kicyunya [14]3 years ago

3 0

Answer:

the second one

Step-by-step explanation:

because the domain (-7) has different ranges, and a function is when the domains have only one range

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

3 years ago

What can be concluded about the line represented in the table? Check all that apply.

motikmotik

The slope is 2.

The slope is 1/2.

The y intercept is 4.

The y intercept is 8

The points (-2,-5) and (8,0) are also on the line

The points (-5,-2) and (1,10) are also in the line.

6 0

3 years ago

Read 2 more answers

KatRina [158]

Answer:

x2+x-4=0

Step-by-step explanation:

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3 years ago

Which equation has a slope of –3/2 and a y-intercept of 5?

Natasha_Volkova [10]

I’m not sure what you’re options are but an equation in Y=mx+b form for this would be y= -3/2x + 5

M is always the slope
B is always the y intercept

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3 years ago

A vehicle uses 1 gallons of gasoline to travel 13 miles. At this rate, how many mile

Brrunno [24]

1 gallon (it’s stayed in the question)

6 0

3 years ago