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Tems11 [23]
3 years ago
14

Need ASAP answer because I don’t not understand

Mathematics
2 answers:
dimaraw [331]3 years ago
6 0

Hello there! The correct answer is B.

Note that in functions, x values cannot repeat. The points are given as (x, y) values, and you can see in the second option there are two -7s in the x values, making it not a function!

<em>I hope this was helpful, have a great rest of your day! If you need further help with this question, let me know!</em>

kicyunya [14]3 years ago
3 0

Answer:

the second one

Step-by-step explanation:

because the domain (-7) has different ranges, and a function is when the domains have only one range

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So, the ball falls 4 \dfrac{1}{4} feet from Sonya's hand to the deck  and 7 \dfrac{7}{8} from the deck to the ground, in total

4\dfrac{1}{4}+7\dfrac{7}{8}=4\dfrac{2}{8}+7\dfrac{7}{8}=(4+7)+\dfrac{2+7}{8}=11+\dfrac{9}{8}=11+1\dfrac{1}{8}=12\dfrac{1}{8}\ feet

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Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

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