All categories

3 years ago

Select all the correct answers. Which equations have infinitely many solutions?

Mathematics

2 answers:

777dan777 [17]3 years ago

4 0

I think it is b and d

guajiro [1.7K]3 years ago

4 0

Answer:

2,4

Step-by-step explanation

all real numbers are solutions, therefore it has infinite many solutions

You might be interested in

If you have 3 cups of pineapple juice how many cups can you make?Juice recipe:Ginger ale:40% orange juice:25% pineapple juice:20

katen-ka-za [31]

If 3 cups is 20% of the whole mixture, then you multiply both numbers by 5 to find the total amount of juice. 3•5=15 cups of juice

8 0

4 years ago

Which phrase describes the variable expression m + 5?

Vedmedyk [2.9K]

5m or m(5)

Have a nice day :)

8 0

3 years ago

Read 2 more answers

If we know the values of the sine and cosine of x and y, we can find the value of cos(x - y) by using the ____ Formula for Cosin

kolbaska11 [484]

Answer:

$\cos(x - y) = \cos(x)\cos(y) + \sin(x)\sin(y)$

Step-by-step explanation:

Given

$\cos(x - y)$

Required

State the formula

From trigonometry identity, the formula of $\cos(x - y)$ is:

$\cos(x - y) = \cos(x)\cos(y) + \sin(x)\sin(y)$

5 0

3 years ago

Solve the following quadratic by completing the square. y = x2 - 6x +2

Nana76 [90]

Answer: $3 \pm \sqrt{7}$

Step-by-step explanation:

$1) \text{ } x^{2}-6x+2=0\\\\2) \text{ } x^{2}-6x=-2\\\\3) \text{ } x^{2}-6x+\left(\frac{-6}{2} \right)^{2}=-2+\left(\frac{-6}{2} \right)^{2}=7\\\\4) \text{ } (x-3)^{2}=7\\\\5) \text{ } x-3 =\pm \sqrt{7} \longrightarrow \boxed{3 \pm \sqrt{7}}$

4 0

2 years ago

21 Maria sold small boxes of candy for $1 and

Anna35 [415]

Answer:

There where 10 more Small boxes sold than Large boxes.

Step-by-step explanation:

This is a typical question that can be solved by obtaining a system of two linear equations and solving for each variable.

In principle Linear Equations are algebraic expressions denoting a relationship between a Dependent variable $y$ and an Independent variable $x$ . In a system of Two Linear equations we have two equations of the same variable sets (thus Two Independent variables) so in this case both $y$ and $x$ will be variable terms.

Now with respect to the question and the given information, here our two Variable terms will be the small and the large boxes.

Given Information:

Small Boxes (lets call them $s$ ) cost $1 per box

Large Boxes (lets call them $l$ ) cost $4 per box
Total Number of Boxes sold is 30
Total Profit from sold Boxes is $60

Thus from the above we can obtain one equation denoting the Total Number of Boxes sold and one equation denoting the Total Profit from sold boxes, respectively, as follow:

$s+l=30$ Eqn(1): Total Number of Boxes

$1s+4l=60$ Eqn(2): Total Profit from sold boxes

Now we have a system of two linear equations which we can solve and find the number of small and large boxes, $s$ and $l$ respectively.

From Eqn(1) we see that

$s=30-l$ Eqn(3).

Plugging Eqn(3) in Eqn(2) we can solve for $l$ as:

$1(30-l)+4l=60$

$30-l+4l=60$ Factored out bracket

$3l=60-30$ Gather similar terms on each side and simplify

$3l=30$

$l=\frac{30}{3}$

$l=10$

Plugging in the value for $l=10$ in Eqn(3) we have

$s=30-10\\s=20$

So we know that they were 10 Large Boxes and 20 Small Boxes sold, thus to answer our question, there where 10 more Small boxes sold than Large boxes.

5 0

4 years ago