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3 years ago

12

5L/s=__________kl/min

1 answer:

Zina [86]3 years ago

6 0

0.3kl/min
hope that helps

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Solve for p. <br> −160=22+8(3p−4)

Aneli [31]

-160=22+8(3p-4)
Use distributive property
-160=22+24p-32
-160=24p-10
Add 10 for both side
-160+10=24p-10+10
-150=24p
Divided 24 for both side
-150/24=24p/24
p=-6.25
Check:
-160=22+8(3p+4)
-160=22+8[3(-6.25)-4]
-160=22+8(-18.75-4)
-160=22+8(-22.75)
-160=22-182
-160=-160. As a result, x=-6.25. Hope it help!

3 0

2 years ago

Read 2 more answers

Charged at midnight. Which ordered pair is a viable

LiRa [457]

こんにちは、これを読んでいただきありがとうございます。私は英語が話せないので、あなたの質問には答えられないと言いたかっただけです。ごめんなさい。

4 0

3 years ago

To which set or sets does the number 7 belong: natural numbers, whole numbers, integers, rational numbers, irrational numbe

Vedmedyk [2.9K]

Answer:

integers

Step-by-step explanation:

hope this is helpful

5 0

2 years ago

Given a rectangular pyramid and a rectangular prism that have the same base and same height, how do their volumes compare? If th

Evgen [1.6K]

Answer:

Part 1) The volume of the prism is 3 times greater than the volume of the pyramid

Part 2) The prism would fill only one-third

Part 3) The cylinder and the cone

Step-by-step explanation:

Part 1) How do their volumes compare?

we know that

The volume of a rectangular prism is equal to

$Vprism=BH$

where

B is the area of the base of rectangular prism

H is the height of the prism

The volume of a rectangular pyramid is equal to

$Vpyramid=\frac{1}{3}BH$

where

B is the area of the base of rectangular pyramid

H is the height of the pyramid

Compare the volumes

$Vprism=BH$ -----> equation A

$Vpyramid=\frac{1}{3}BH$ -----> equation B

substitute equation A in equation B

$Vpyramid=\frac{1}{3}Vprism$

$Vprism=(3)Vpyramid$

The volume of the prism is 3 times greater than the volume of the pyramid

Part 2) If the pyramid was full of water, how much of the prism would it fill up?

Remember that

$Vpyramid=\frac{1}{3}Vprism$

therefore

The prism would fill only one-third

Part 3) Name another pair of three-dimensional objects that have a relationship similar to this

we have the cylinder and the cone

The volume of the cylinder is equal to

$Vcylinder=\pi r^{2}h$

The volume of the cone is equal to

$Vcone=\frac{1}{3}\pi r^{2}h$

Compare the volumes

$Vcylinder=(3)Vcone$

The volume of the cylinder is 3 times greater than the volume of the cone

3 0

3 years ago

Find the value of x and y.

spayn [35]

By the geometric mean theorem,

$\frac{y}{4}=\frac{12}{y} \\ \\ y^{2}=48 \\ \\ \boxed{y=4\sqrt{3}}$

So, by the Pythagorean theorem,

$12^{2}+(4\sqrt{3})^{2}=x^{2}\\\\144+48=x^{2}\\\\192=x^{2}\\\\\boxed{x=8\sqrt{3}}$

7 0

1 year ago