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2 years ago

Which angle is coterminal with 112°

Mathematics

1 answer:

Vesna [10]2 years ago

8 0

Positive angles that are coterminous with 112 degrees are
472 degrees & 832 degrees

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A dog weighs 0.5 pound when it is born.

Vesnalui [34]

Answer:

*It gains weight as it grows, and is 35 pounds when it is 1 year old.

*Then the dog stays the same weight for the rest of its life.

*It lives to be 15 years old.

What is the domain of the function representing the weight, in pounds, of the dog in terms of its age in

years?

A. 0 to 1 year

B. 0 to 15 years

C. O to 35 pounds

D. 0.5 to 35 pounds

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2 years ago

A dilation maps the point (24,36) to (16,24). The scale factor of the dilation is

Vika [28.1K]

Answer:

The scale factor of the dilation is 2/3

Step-by-step explanation:

point (24,36) to (16,24)

16/24 = 2/3

24/36 = 2/3

Answer

The scale factor of the dilation is 2/3

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2 years ago

What is a irregular concave polygon

Anvisha [2.4K]

Answer:

An irregular polygon is any polygon that is not a regular polygon. It can have sides of any length and each interior angle can be any measure. They can be convex or concave, but all concave polygons are irregular since the interior angles cannot all be the same.

Step-by-step explanation:

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2 years ago

!!20 points and Brainliest please help!!!

vitfil [10]

D) ac + ad + bc + bd

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1 year ago

Read 2 more answers

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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2 years ago