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Dmitriy789 [7]
3 years ago
14

Determine whether the function is periodic. If it is periodic, find the period.

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer

a) 2π

Step-by-step explanation:

We can easily solve this question by using a graphing calculator or any plotting tool, to check if it is periodic.

The function is

f(x) =  3*sin(2*x) + 4*cos(3*x)

Which can be seen in the picture below

We can notice that f(x) is periodic. It has periodic amplitudes, and the function has a period T = 6.283   ≈ 2π

The maximum and minimum values are

Max = 6.695

Min = -6.695

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Answer:

subtract 6 from both sides.

-5c = -10

then divide both sides by -5 (negative divided by a negative is a positive)

c = 2

Step-by-step explanation:

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What is h(x)=4x+1 if the value of h is (-3)
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Salna, it is a question about simple function

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The CEO of a large manufacturing company is curious if there is a difference in productivity level of her warehouse employees ba
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Answer:

The test statistic is z = -2.11.

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Group 1: Sample of 35, mean of 1276, standard deviation of 347.

This means that:

\mu_1 = 1276, s_1 = \frac{347}{\sqrt{35}} = 58.6537

Group 2: Sample of 35, mean of 1439, standard deviation of 298.

This means that:

\mu_2 = 1439, s_2 = \frac{298}{\sqrt{35}} = 50.3712

Test if there is a difference in productivity level.

At the null hypothesis, we test that there is no difference, that is, the subtraction is 0. So

H_0: \mu_1 - \mu_2 = 0

At the alternate hypothesis, we test that there is difference, that is, the subtraction is different of 0. So

H_1: \mu_1 - \mu_2 \neq 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = \mu_1 - \mu_2 = 1276 - 1439 = -163

s = \sqrt{s_1^2+s_2^2} = \sqrt{58.6537^2+50.3712^2} = 77.3144

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{-163 - 0}{77.3144}

z = -2.11

The test statistic is z = -2.11.

7 0
3 years ago
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