<em>THE</em><em> </em><em>RIGHT</em><em> </em><em>ANSWER</em><em> </em><em>IS</em><em> </em><em>OF</em><em> </em><em>THIRD</em><em> </em><em>OPTION</em><em>.</em>
<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>.</em><em>.</em><em>.</em>
Given:
The expression is:

To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,

[Using BODMAS]

In option B,

[Using BODMAS]

In option C,


In option D,

[Using BODMAS]

After the calculation, we have
and
.
Therefore, the correct options are B and D.
Part B: From part A, it is clear that

Therefore, the correct option is C.
Answer:
<em>First even integer: 6</em>
Step-by-step explanation:
<u>Inequalities</u>
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:

Operating:

Subtracting 2 and 2x:

Simplifying:

Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.
Answer:
C AND D
Step-by-step explanation:
AP EX Confirmed
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