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Dmitriy789 [7]
3 years ago
14

Determine whether the function is periodic. If it is periodic, find the period.

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer

a) 2π

Step-by-step explanation:

We can easily solve this question by using a graphing calculator or any plotting tool, to check if it is periodic.

The function is

f(x) =  3*sin(2*x) + 4*cos(3*x)

Which can be seen in the picture below

We can notice that f(x) is periodic. It has periodic amplitudes, and the function has a period T = 6.283   ≈ 2π

The maximum and minimum values are

Max = 6.695

Min = -6.695

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The gcf of the numbers are 15
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If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

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2 years ago
50 POINTS
ikadub [295]
You would have to do 6x2= 12 so it’s 12 outcomes
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3 years ago
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What value of n makes the equation true?
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2/3 n = -12 Write equation

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n = -18 Answer




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3 years ago
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Can you help me with number 3? Please!!!!
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Answer:

D

Step-by-step explanation:

Take it step by step.

The area of a rectangle is width times length.

We know the length is 7 since it's given, and we can find the width by adding shared sides of the square and triangle.

So the width is 10 + 14 or 24

That means the area of the rectangle is 7 * 24

The area of the second rectangle is 12 * 14, since they are both given.

Finally, the area of the triangle is 1/2 of the base times height and we can find the height by looking at the shared side and using the definition of a rectangle.

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