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hoa [83]
3 years ago
15

how many meters are equal to 5,253 centimeters? use how the placement of the decimal point changes when dividing by power of 10

to help you​
Mathematics
1 answer:
motikmotik3 years ago
3 0

Answer:

52.53\ \text{meters}

Step-by-step explanation:

1\ \text{meter}=100\ \text{centimeter}

1\ \text{centimeter}=\dfrac{1}{100}\ \text{meter}

In the question the quantity that is required to be converted to meters is 5253 centimeters.

5253\ \text{cm}=5253\times \dfrac{1}{100}\\ =52.53\ \text{meters}

So, the required measurement in meters is 52.53\ \text{meters}.

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9 - x = 6; x = 15 6x = 24; x = 6 35 = 5x; x = 7 x + 10 = 21; x = 31 <br> which one is right
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35 = 5x ; x = 7

Step-by-step explanation:

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If h(x)=-2x-10 ,find h(-4)
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Answer:

h(-4) = -2

Step-by-step explanation:

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8 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
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