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Xelga [282]
3 years ago
11

Find each measurement indicated.

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

D) 24

explanation:

Sana makatulong

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What is g in 7h+2f-2g=17.15
drek231 [11]
G = (7h + 2f + 3c - 17.15)/2
7 0
3 years ago
The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?
MaRussiya [10]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}

~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

3 0
1 year ago
Please help me out thank you very much? It is due 03/01/2021
kogti [31]

Answer:

number 13 is false or no

Step-by-step explanation:

example: 5x5 = 25

25-14 = 11

5x3 = 15

so false

7 0
3 years ago
Read 2 more answers
Q3. Kylie sits two maths test. She scores 19/25 in the first one, and 16/20 in the second one.
Rina8888 [55]
She done better at the 2nd test because she only got 4 wrong but on the first test she got 6 wrong.
7 0
3 years ago
Read 2 more answers
A woman standing on a hill sees a flagpole that she knows is 65 ft tall. The angle of depression to the bottom of the pole is 14
Oliga [24]

Answer:

Let the distance between woman and pole be "x".

From diagram,

In ΔOAB,

tan 18 = \frac{Perpendicular}{Base}

tan 18 =  \frac{65 -y}{x}

∴ x =  \frac{65 -y}{tan 18} ................ (1)

In ΔOBC

tan 14 = \frac{Perpendicular}{Base}

tan 14 =  \frac{y}{x}

y = x × tan 14 ..............(2)

equating (2) in (1), we get;

x = \frac{65}{tan 18 + tan 14}

x = \frac{65}{0.574}

∵ tan 18 + tan 14 = 0.574

<em>∴ x = 113.2 ft</em>

<em>i.e. The her distance from the pole is 113.2 ft.</em>

3 0
3 years ago
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