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3 years ago

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parachutist's rate during a free fall reaches 65 meters per second. What is this rate in feet per second? At this rate, how many

feet will the parachutist fall during 2 seconds of free fall? In your computations, assume that 1 meter is equal to 3.3 feet

1 answer:

nataly862011 [7]3 years ago

8 0

The feet per second rate- 214.5 ft per sec

the rate for 2 sec is 429 ft per sec

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Step-by-step explanation:

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The equation can be written is point slope form.

The standard form of point slope equation is:

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Finding slope m:

Slope can be found by using formula:

$slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}$

So, slope is $\frac{1}{3}$

Now finding y-intercept b

Putting slope $\frac{1}{3}$ and point(-6,-7)

$y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5$

So, value of b is -5

Putting values to find the equation:

$y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5$

So, linear equation that passes through the two points (-6, -7) and (3, -4) is $y=\frac{1}{3}x-5$

Keywords: Linear Equation,

Learn more about Linear Equation at:

#learnwithBrainly

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