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3 years ago

Can Someone help me?

Mathematics

1 answer:

aleksandrvk [35]3 years ago

6 0

I think the answer is A. 3.

B. no, to big a number

C. no, to small a number

D. no, again, too big a number.

Have a nice day and hope this helps!

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I need help with 3 , 7 ,4 and 8

Drupady [299]

Solution:

Question 3:

The image below gives a vivid explanation of the question

Concept:

The sum of angles in a triangle is

$=180^0$ $\begin{gathered} \angle A+\angle B+\angle C=180^0 \\ \angle A=61^0 \\ \angle B=90^0 \\ \angle C=4f+1 \end{gathered}$

By substituting the values, we will have

$\begin{gathered} \angle A+\angle B+\angle C=180^0 \\ 61^0+90^0+4f+1=180^0 \\ \text{collect similar terms, we will have} \\ 61+90+1+4f=180^0 \\ 152^0+4f=180^0 \\ 4f=180-152^0 \\ 4f=28^0 \\ \text{Divide both sides by 4} \\ \frac{4f}{4}=\frac{28}{4} \\ f=7^0 \end{gathered}$

Hence,

The final answer is f = 7°

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1 year ago

Write the equation of a line that has a slope 1/3 and y-intercept 4.

tangare [24]

Y=mx+b, where m represents the slope and b represents the y-intercept. If you plug in the numbers, you get the equation, y=(1/3)x+4

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3 years ago

Find the distance and displacement for the following figures :

Vinil7 [7]

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters

<h3>How to find the distance and displacement in each trajectory</h3>

The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the <em>initial</em> and <em>final</em> point of a trajectory. Then, we have the following results for each case:

Case I

Distance

d = 5 m + 0.5π · (7 m)

d ≈ 15.996 m

Displacement

$D = \sqrt{(12\,m)^{2}+(7 m)^{2}}$

D ≈ 13.892 m

Case II

Distance

d = 8 · (60 cm)

d = 480 cm

Displacement

$D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}$

D ≈ 339.411 cm

To learn more on displacement: brainly.com/question/11934397

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2 years ago

What is the reciprocal of 453463.432849

Anvisha [2.4K]

Answer: 0.00000220524

Step-by-step explanation:

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3 years ago

Members of the pep club were selling raffle tickets for $1.50 and $5. The number of $1.50 tickets sold was two less than four ti

marysya [2.9K]

Answer:

see below

Step-by-step explanation:

1.5x + 5y = 1152

x = 4y – 2

We can substitute the second equation into the first equation

Which one-variable linear equation can be formed using the substitution method?

1.5(4y-2) +5y = 1152

Distribute

6y -3 +5y = 1152

Combine like terms

11y-3 = 1152

Add 3 to each side

11y-3+3 = 1152+3

11y = 1155

Divide each side by 11

11y/11 = 1155/11

y = 105

How many $5 raffle tickets were sold?

105 5 dollar tickets were sold

Now we need to find the number of 1.50 tickets

Which equation can be used to determine how many $1.50 raffle tickets were sold?

x = 4y – 2

x = 4(105) -2

=420-2

= 418

How many $1.50 raffle tickets were sold?

418 $1.50 tickets were sold

3 0

3 years ago

Read 2 more answers