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Studentka2010 [4]
3 years ago
13

Solve this equation with variables on both sides- 8x-19=-3x-41 Show work

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0
8x-19=-3x-41
+3x +3x
11x-19=-41
+19 +19
11x=-22
÷11 ÷11
x=-2
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Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
Juan spins two different fair spinners. One spinner has numbers 1 through 8. The other has letters A through F. What is the prob
Evgen [1.6K]

Answer:

...

Step-by-step explanation:

7 0
2 years ago
PLEASE HELP<br> Solve for x.<br><br> -6x+14&lt;-28 OR 9x+15&lt;= -12
Anastaziya [24]

Answer: For -6+14<-28, the answer is....

Inequality form : x>7

For 9x+15<-=12, the answer is...

Inequality form : x <= -3

Step-by-step explanation: Isolate  the variable by dividing each side by factors that don't contain the variable. (THIS IS FOR BOTH ANSWERS!!)

Hope this helps you out.

5 0
2 years ago
A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen
serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

P=\frac{7}{579}=0.121

b) The probability that both are defective is given by:

P=\frac{8}{580}*\frac{7}{579}= 0.000167

c) The probability that both are acceptable is given by:

P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

P=\frac{6}{578}}= 0.0104

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

P=\frac{7}{578}= 0.01211

f) The probability that all three are defective is given by:

P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731

7 0
3 years ago
People people plsss i need your help I'm about to take a geometry final test and i need your help passing it... sooo
attashe74 [19]

Kk I’ll help ya bro!

6 0
3 years ago
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