

Multiply both numerator and denominator of
by the complex conjugate of the denominator, -2+9i.

Multiplication can be transformed into difference of squares using the rule:
.

By definition, i² is -1. Calculate the denominator.

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

Do the multiplications in
.

Combine the real and imaginary parts in -10+45i+6i+27.

Do the additions in
.

Divide 17+51i by 85 to get
.

The real part of
is
.

Answer:
The correct option is D. 2/7
Step-by-step explanation:
Consider the provided information.
There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.
We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.
We want to select Andrew and 3 others but not Karen in the group.
Thus, the number of ways to select 3 member out of 8-2=6
(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)
The required probability is:

Hence, the correct option is D. 2/7
Answer:
15*C
Step-by-step explanation:
The temperature rises by 2.4 every 3 cycles per second. So you would have to keep the pattern going.
6 cycles p/second = 19.8*C
3 cycles p/second = 17.4*C
0 cycles p/second = 15.0*C
So, because 0 cycles means the engine is resting, 15*C would be the answer.
Answer:
2.5
Step-by-step explanation: