The diagonal is the distance between opposite corners...
d=x^2+y^2
d^2=260100
d=510 feet
The GCF of 72 is 60 is 12.
The slope of the line is 1. the equation would be y=x-3
Answer:
Horizontal stretch by a factor of ½.
Step-by-step explanation:
We were given the parent function as:
![y = \sqrt[3]{0.5x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7B0.5x%7D%20)
This was transformed to:
![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
Let
![g(x) = \sqrt[3]{0.5x}](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B0.5x%7D%20)
and
![f(x) = \sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
Then:

Hence the parent function has been stretched horizontally by a factor of 1/2 to obtain the transformed function.