Answer:
the third circle.
Step-by-step explanation:
Answer:
option 3
Step-by-step explanation:
![(4 + 3) \sqrt[5]{x {}^{2}y } = 7 \sqrt[5]{ {x}^{2}y }](https://tex.z-dn.net/?f=%284%20%2B%203%29%20%5Csqrt%5B5%5D%7Bx%20%7B%7D%5E%7B2%7Dy%20%7D%20%3D%207%20%20%5Csqrt%5B5%5D%7B%20%7Bx%7D%5E%7B2%7Dy%20%7D%20)
Answer:
B: 12.9
Step-by-step explanation:
If A B and C are the alternatives, the answer is B: 12.9
The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.
And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6
Any questions, comment.
<span>Simplifying
7p + 2 = 5p + 8
Reorder the terms:
2 + 7p = 5p + 8
Reorder the terms:
2 + 7p = 8 + 5p
Solving
2 + 7p = 8 + 5p
Solving for variable 'p'.
Move all terms containing p to the left, all other terms to the right.
Add '-5p' to each side of the equation.
2 + 7p + -5p = 8 + 5p + -5p</span>
very simple, we use the formula sin(a+b)=sinacosb +
sinbcosa and sin(20)=2sinacosa
5pi = 2pi/3+3pi/3,
First, we use sin(a+b)=sinacosb + sinbcosa
sin(5pi/3)=sin(2pi/3+3pi/3)=
sin(2pi/3+pi)=
sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)
but we know that sin(pi)=
0, and cos (pi) = -1, so sin(5pi/3)=
- sin(2pi/3)
now, use sin(2a)=2sinacosa,
sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)
sin<span>(5pi/3)=
-2sin(pi/3)cos(pi/3)</span>
<span>sin(pi/3)= 0.86,
cos(pi/3)=0.5, finally we have </span>sin<span>(5pi/3)= -0.86 x 0.5= -0.43</span>
