The possibilities are endless
If we're talking between 1-20
then the numbers divisible by 2 and 6 are
18,12,6
y = x^2 + 2x...eqn 1
y = 3x + 20...eqn 2
subst for y in eqn 1...
=> x^2 +2x = 3x +20
=> x^2 - x - 20 =0
=> (x-5) (x+4) =0
=> x = 5 or -4
for x =5, y = 35 (sub for x in eqn 1 or 2)
for x = -4, y = 8 (sub for x in eqn 1 or 2)
Answer:
chicken and chicken
Step-by-step explanation:
just took the test
Surface area of the cylinder is 294π in².
Step-by-step explanation:
- Step 1: Surface area of a cylinder = 2πrh + 2πr² Here, r = 7 in, h = 14 in
⇒ Surface Area = 2 × π × 7 × 14 + 2 × π × 7 × 7
= π (196 + 98) = 294π in²
The standard equation for circumference
CC= 2pi(D/2)
plug in variables
CC=2pi(5656/2)
so the equation would be
CC=(2)(pi)(2828)
