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shusha [124]
3 years ago
6

What is x: 1. x ÷ 3/5 = 10/9 2. 1/2x = 2/15

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

1. x = 2/3

2. x = 4/15

I hope it helps you

:-()

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(Sinθ-cosθ)(sinθ+cosθ)=1-2cos^2θ
ohaa [14]

Answer:

See below

Step-by-step explanation:

( \sin \theta -  \cos \theta)( \sin \theta  +  \cos \theta) = 1 - 2 { \cos}^{2}  \theta \\  \\ LHS   = ( \sin \theta -  \cos \theta)( \sin \theta  +  \cos \theta)  \\  \\  =  \sin^{2}  \theta -  \cos^{2}  \theta \\  \\  =1 -  \cos^{2}  \theta -  \cos^{2}  \theta \\( \because  \sin^{2}  \theta =1 -  \cos^{2}  \theta)  \\  \\  = 1 - 2 { \cos}^{2}  \theta   \\ = RHS

Thus proved

8 0
3 years ago
Help please.. its quiet easy anyway xd
padilas [110]

Answer:

An equilateral triangle is a triangle in which all three sides are equal. An equilateral triangle is also equiangular, in which all three internal angles are also congruent to each other and are each 60°.

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8 0
4 years ago
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You earn 100 brainly points if you help me. Triangle ABC below has a right angle C and a height CD. (A height in a triangle conn
melamori03 [73]

Answer:

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Find the value of x and y​
Alex777 [14]
X and y will be both 5.
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5 0
3 years ago
A bus and a car leave from the same city traveling in opposite directions. The bus leaves 2 hours before the car does. The bus t
nikitadnepr [17]

Normally, I would pass right by this question, because it is so complicated
and there are so many numbers in it.  But I've allowed myself to become
seduced by the bounty of a full 5 points waiting at the end of the rainbow,
and I decided to rush in where more reasonable people would rightly fear
to tread.

The answer is a number, that represents "after how many hours".  So we
need to know how many hours AFTER WHAT.  The question is not very
clear on when the beginning of time is, so I need to decide.  I'm going to
say that the time when the bus leaves is the beginning of time.  And I'm
going to call  ' H '  the number of hours AFTER the bus leaves.

-- The bus covers 50 miles every hour.  So 'H' hours after the bus leaves,
the bus is  50H  miles away from the city, in some direction.

-- The car leaves 2 hours later.  So 'H' hours after the bus leaves, the car
has only been traveling for  (H-2)  hours.

-- The car covers 70 miles every hour.  So 'H' hours after the bus leaves,
the car is  (70)x(H-2)  miles away from the city, in the OTHER direction.

-- Since the bus and the car are moving in opposite directions, the distance
between the bus and the car is the SUM of the distances each one covers.

     'H' hours after the bus leaves, they are  (50H) plus (70)(H-2) miles apart.

What we need to figure out is:  When is that distance 800 miles ?


The distance between them at 'H' hours after the bus leaves is

                                                            (50H) plus (70)(H-2) miles

Eliminate the first parentheses:             50H  +  (70)(H-2)

Eliminate the rest of the parentheses:   50H  +  70H - 140

Combine the terms with 'H' in them:         120H - 140

So here's the equation:                            120H - 140 = 800

Add  140  to each side:                            120H          =  940

Divide each side by  120 :                             H  =  7.8333 hours
                                                                           =  7 and 5/6 hours
                                                                           =  7 hours and 50 minutes
                                                                                 after the bus leaves.

Check:

Assume that  H = 7 hrs 50 minutes  (7 and 5/6 hours)
The bus has covered  (50 x 7-5/6) = 391 and 2/3 miles.
 
The car has been traveling for only  5 and 5/6 hours
The car has covered   (70) x (5-5/6) =  408 and 1/3 miles

How far apart are they ?   (391-2/3) + (408-1/3) =  800 miles !           YAY!   


Note:  If the book or the homework sheet wants to count the hours
after the CAR leaves, then the answer is  5-5/6 hours, not 7-5/6 . 

7 0
3 years ago
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