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Natalija [7]
3 years ago
7

. Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4

. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6​
Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6​

Step-by-step explanation:

.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6​

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Answer:

17. a)

Step-by-step explanation:

17.

f(x) =x/2, then f(x-3)=(x-3)/2

x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)

f(x-3)+3=0+3=3

18.

f(x) =x/2

f(x-2) for x=5 is f(5-2)=f(3)=3/2

f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2

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3 years ago
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Answer:

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Step-by-step explanation:


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Which law would you use to simplify the expression?
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A. quotient of Powers

Step-by-step explanation:

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Question 12 (1 point)
Paraphin [41]
<h3>Answer:   5</h3>

=================================================

Explanation:

Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:

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Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.

In short, this means that the degree of each monomial term is 2.

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Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.

We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.

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This pattern continues.

In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.

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7

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