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3 years ago

14

What is $120 plus 9.75%

1 answer:

iris [78.8K]3 years ago

4 0

Answer:

131.7

Step-by-step explanation:

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X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?

lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer: {x = 20/13 , y = 16/13 , z = 120/13

8 0

3 years ago

Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?

Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

Step-by-step explanation:

Given the equation

$5x - y = 12$

converting the line into the slope-intercept form y = mx+b, where m is the slope

$-y = 12-5x$

$y = 5x-12$

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

$y-y_1=m\left(x-x_1\right)$

$y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)$

$y-3=-\frac{1}{5}\left(x+2\right)$

Add 3 to both sides

$y-3+3=-\frac{1}{5}\left(x+2\right)+3$

$y=-\frac{1}{5}x+\frac{13}{5}$

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

5 0

3 years ago

70 brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11111

Evgesh-ka [11]

Answer:

nice job man

Step-by-step explanation:

keep it up man

6 0

2 years ago

What is the solution set for the open sentence with the given replacement set?

kenny6666 [7]

The Answer Is 6 Because -x=7-13
-x=-6
X=6

7 0

3 years ago

An element with mass 510 grams decays by 26.3% per minute. How much of the element is remaining after 7 minutes, to the nearest

Eddi Din [679]

A decay rate of 26.3% per minute means that for every minute that passes, there remains 73.7% of the amount of the substance available at the end of the previous minute.

If $a_0$ is the starting amount, and $a_i$ is the amount left after $i$ minutes, then

$a_1=0.737a_0$

$a_2=0.737a_1=0.737^2a_0$

$a_3=0.737a_2=0.737^3a_0$

and so on, such that

$a_7=0.737^7a_0$

We have $a_0=510$ grams at the start, so after 7 minutes we're left with

$a_7=0.737^7(510)\approx60.2\,\rm g$

4 0

3 years ago