The line that passes through (-2, 1) and (8, 2) is:
y = (1/10)*x + 12/10
<h3>How to find the equation of the line?</h3>
I assume you want to find the equation of the line that passes through (-2, 1) and (8, 2).
A general linear equation is written as:
y = a*x + b
If the line passes through two points (x₁, y₁) and (x₂, y₂), then the slope can be written as:
![a = \frac{y_2 - y_1}{x_2 - x_1}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7By_2%20-%20y_1%7D%7Bx_2%20-%20x_1%7D)
In this case, we know that it passes through (-2, 1) and (8, 2), then:
![a = \frac{2 - 1}{8 - (-2)} = 1/10](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B2%20-%201%7D%7B8%20-%20%28-2%29%7D%20%3D%201%2F10)
Then the line is:
y = (1/10)*x + b
To find the value of b, we use one of the given points, for example if we use (8, 2), it means that when x = 8, we must have y = 2.
2 = (1/10)*8 + b
2 - 8/10 = b
20/10 - 8/10 = b
12/10 = b
Then the linear equation is:
y = (1/10)*x + 12/10
If you want to learn more about linear equations:
brainly.com/question/1884491
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