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il63 [147K]
3 years ago
9

Estimate the square root of 300 and 190

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0

Answer:

22

Step-by-step explanation:

ikadub [295]3 years ago
3 0
For 300..about 17
For 190..about 14

300: 17.320
190: 13.784
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Help due Monday......
pantera1 [17]

Step-by-step explanation:

<u>5</u><u>)</u><u> </u>2.4×10^-5 / 4.5×10^-11

  • 2.4×10^-5= 0.000024
  • 4.5×10^-11= 0.000000000045

=0.000024/0.000000000045

=24/1 × 1,000,000/45

=24,000,000/45

=533,333.33°

=5.33333°×10^5

**NOT SURE ABOUT THIS QUESTION

<u>6</u><u>)</u><u> </u>(4,-2)

<u>7</u><u>)</u> --------

<u>8</u><u>)</u>

  1. 2x + 3 = 5x - 2

  • 2x - 5x = - 2 - 3
  • -3x = -5
  • x = -5/-3
  • x = 1.66°

  1. 6x + 4 = 6x + 4
  • 6x - 6x = 4 - 4
  • 0x = 0

  1. 2 (2x + 3) = 8x - 2
  • 4x + 6 = 8x - 2
  • 4x - 8x = -2 - 6
  • -4x = -8
  • x = -8/-4
  • x = 2

  1. -3x + 2 = -3x + 5
  • -3x + 3x = 5 - 2
  • 0x = 3

Letter be has no solution because it is broken down as "0x = 0"

6 0
3 years ago
How many points did the player with the fewer points score?
zmey [24]
B. 54
Because 54+13=67
67+54=121
3 0
3 years ago
Planet Mass (in grams) Jupiter 1.989 ∙ 10^30
Fiesta28 [93]
400 should be the answer. Hope this helps!
6 0
3 years ago
Factor completely: x^2-y^2-1.5(x-y)
guapka [62]

Answer: x^2 - y ^2 − 1.5x + 1.5y

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Consider the problem $minimize$ $f(x)=x^4-1$. solve this problem using newton's method. start from $x_0=4$ and perform three ite
stellarik [79]
F(x)=x⁴-1
f'(x)=4x³
Newton’s Method: x[n+1]=x[n]-f(x[n])/f'(x[n]); x[n+1]=x[n]-(x[n]⁴-1)/4x[n]³
x₁=3.00390625
x₂=2.26215...
x₃=1.7182...

X'=X-(X⁴-1)/4X³=X-X/4+1/4X³ is a symbolic way of writing the recursive formula, where X' represents the next iteration.
When X'≈X, -X/4+1/4X³≈0; so X/4≈1/4X³; X≈1/X³, so X⁴≈1 and X⁴-1≈0. But this is f(x)≈0. Hence Newton’s Method converges to a solution.
The rate of change is x[n+1]-x[n]=-(x[n]⁴-1)/4x[n]³=x[n]/4-1/4x[n]³ or symbolically -X/4+1/4X³.
Note that the method converges to one solution. A different x₀ will possibly converge to the solution x=-1.
5 0
3 years ago
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