The maxima of f(x) occur at its critical points, where f '(x) is zero or undefined. We're given f '(x) is continuous, so we only care about the first case. Looking at the plot, we see that f '(x) = 0 when x = -4, x = 0, and x = 5.
Notice that f '(x) ≥ 0 for all x in the interval [0, 5]. This means f(x) is strictly increasing, and so the absolute maximum of f(x) over [0, 5] occurs at x = 5.
By the fundamental theorem of calculus,
The definite integral corresponds to the area of a trapezoid with height 2 and "bases" of length 5 and 2, so
Answer:
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Step-by-step explanation:
7 + 13 = 20
13 + 7 = 20
13 – 13 = 0
13 – 0 = 13
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 0 = 7
6 + 0 = 6
13 – 0 = 13
13 – 13 = 0
7 + 6 = 13
13 = 7 + 6
13 – 6 = 7
7 = 13 – 6
Step-by-step explanation:
1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then
2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then
3) the length of AB, AC and AD are:
4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).
Okay we'll start easy
46*93
We will take 6*3 which is 18.
40*3 which is 120
6*90 which is 540
40*90 which is 3600
Now add up those
18+120+540+3600 which is 4278
So the missing numbers.
3._00 is going to be 3600
5_0 is going to be 540
_20 is going to be 120
1_ is going to be 18
4._78 is going to be 4.278
Hope this helped. ^~^
Just count up from 9:30. 5 and 1/2 hours is the answer
