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3 years ago

Pleaseeeeeeeee help meeeeEEEEEEEE IM HAVING A BREAKDOWN JUST PLEAAE HELPPPP

Mathematics

1 answer:

katovenus [111]3 years ago

5 0

Answer:

all you got to do at the Sheldon also picks tomatoes from his garden. He picked 5 310 kg, but 1.5 kg were rotten and had to be thrown away. How many kilograms of tomatoes were not rotten? Write an equation that shows how you reached your answer.

Step-by-step explanation:

Sheldon also picks tomatoes from his garden. He picked 5 310 kg, but 1.5 kg were rotten and had to be thrown away. How many kilograms of tomatoes were not rotten? Write an equation that shows how you reached your answer.

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Write a recursive formula for 3, 20, 37, 54

Dima020 [189]

A(n)=A(n-1)+17 with A(1)=3

What is inside the parentheses can also be written as a subscript.
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3 years ago

Please...............

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Answer: A and D

Step-by-step explanation:

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3 years ago

Sin 31 / 2 cos 59<br>evatuate with out using table

xxTIMURxx [149]

Answer:

Find the exact value using trigonometric identities.

0.13763793

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3 years ago

First question, Deangelo babysits for his neighbor. Over a two week long time, he babysits 3.8 hours the first week and 5.25 hou

weeeeeb [17]

Don't you just add, though?

3.8 + 5.25 = 9.05 hours?

7 0

3 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago