Answer:
The yield is 5.974%
Step-by-step explanation:
We proceed as follows ;
coupon rate = Annual coupon payment/bond face value.
The face value is the original amount which the bond was bought and that is $515 according to the question. While the coupon rate is 5.8%
mathematically, annual coupon payment = coupon rate * bond face value = 0.058 * 515 = $29.87
mathematically;
current yield = Annual coupon payment/bond price
current yield = 29.87/500
= 0.05974 or simply 5.974%
so the answer is c. 5.6%
Step-by-step explanation:
Answer:
10 minutes
Step-by-step explanation:
Let the number of minutes = x
It costs Guido $0.20 per minute to forward voicemail messages as texts to his cell phone. He already spent $4 in forwarding messages this month.
For Guido
$4 + 0.20x
His mom has spent $2 forwarding messages. It costs her $0.40 per minute so she can call long distance.
For his mum
$2 + 0.40x
Guido's mom said they have to spend the same amount.
Equating both Equations together
$4 + 0.20x = $2 + 0.40x
$4 - $2 = 0.40x - 0.20x
2 = 0.20x
x = 2/0.20
x = 10 minutes
Guido can talk for 10 minutes
75/100 = 0.75
--------------------
12 x 0.75 = 9
* The mine elevator travels a
distance of 9 metres per minute.
---------------------
After 2 minutes, the mine elevator
would've travelled 18 metres,
therefore your answer is:
A: -18 metres
So, given a quadratic function, y = ax2<span> + bx + c, when "a" is positive, the </span>parabola<span> opens upward and the vertex is the </span>minimum<span> value. On the other hand, if "a" is negative, the graph opens </span>downward<span> and the vertex is the </span>maximum<span> value. To put it in complicated terms. Or when A is positive the graph is shaped like a U but if A is negative the graph is an upside down U
</span>
Let
be the line given by the vector equation
.
First, we use the director vectors of the lines L1 and L2 to get the
vector equation of the plane containing them, which we denote by
. This is,

We observe that
. Therefore, the vector equation of
defines a plane and
is a normal vector to 
Finally, the vector equation for the wanted plane, which we denote by
, is
Thus, if
, then
and since
is parallel to
, then it is perpendicular to
.