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MariettaO [177]
2 years ago
13

Pleaseeeeeeeee help meeeeEEEEEEEE IM HAVING A BREAKDOWN JUST PLEAAE HELPPPP

Mathematics
1 answer:
katovenus [111]2 years ago
5 0

Answer:

all you got to do at the Sheldon also picks tomatoes from his garden.  He picked 5 310 kg, but 1.5 kg were rotten and had to be thrown away.  How many kilograms of tomatoes were not rotten?  Write an equation that shows how you reached your answer.

Step-by-step explanation:

Sheldon also picks tomatoes from his garden.  He picked 5 310 kg, but 1.5 kg were rotten and had to be thrown away.  How many kilograms of tomatoes were not rotten?  Write an equation that shows how you reached your answer.

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mr banks left work at 5 15 P.M it took him 1 1/4 hours to drive home . at what time did mr banks drive home? worth 22 points
Zepler [3.9K]
Using the information that you've provided, I would say that Mr. Banks drove home at 5:15, but if you're asking what time he arrived home that would be at 6:30. :))
7 0
3 years ago
Read 2 more answers
An image of a book shown on a website is 1.5 inches wide and 3 inches tall on a computer monitor. The actual book is 9 inches wi
valentina_108 [34]

Answer: 1 inches = 6 inches

Step-by-step explanation:

From the question, we are informed that an image of a book shown on a website is 1.5 inches wide and 3 inches tall on a computer monitor and that the actual width of the book is 9 inches.

Based on the above analysis, the scale that is being used for the image is:

= 1.5/9

= 1/6

= 1:6

Therefore, the scale is used is:

1 inches = 6 inches

3 0
3 years ago
HELP!! <br> 9. What is the area of triangle AOB?
Akimi4 [234]

Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.

<h3>What is the area of the right-angle triangle?</h3>

The area of the right-angle triangle is given as

A = 1/2 x B x H

Where B is the base and H is the height of the right triangle.

We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.

α₁ = 40°

AO = OC = 7.8 cm

Then the area of the triangle will be

Area = 1/2 x 7.8 x 7.8 x tan40°

Area = 22.53 square cm

More about the area of the right-angle triangle link is given below.

brainly.com/question/16653962

#SPJ1

5 0
1 year ago
A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student
umka2103 [35]

Answer:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X_{M}= 69.8 represent the mean for the age of grandmother

\bar X_{F}= 71.6 represent the mean for the age of grandfather

s_{M}= 8.38 represent the sample deviation for the age of grandmother

s_{F}= 6.65 represent the sample deviation for the age of grandfather

n_M = n_F= 10

Solution to the problem

For this case the confidence interval is given by:

(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n_M +n_F-2=10+10-2=18

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that t_{\alpha/2}=2.101

And replacing we got:

(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908  

(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308  

So then the confidence interval for the difference of means is given by:

-8.908 \leq \mu_M -\mu_F \leq 5.308

5 0
3 years ago
What is 11- 9 1/4 simplfy
bija089 [108]

1 and 3/4 is the answer!

Hope this helps! May I have brainliest? :D

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