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jeyben [28]
3 years ago
11

A rectangular playground has a width of 540 feet and a length of 810 feet. Martina makes a scale model of the playground using a

scale of 4cm: 30ft.
What are the dimensions of Martina's scale model?
Mathematics
1 answer:
densk [106]3 years ago
4 0
66.67cm x 108cm.
To know that dimensions of marking scale model we have to calculate how many centimeters are 540 feet and 810 feet we know that’s 4 cm represents 30 feet now we used in the ruler of 3 to 4 cm represents 30 feet 500’ and 800 feet how many centimeters would it be 500 feet 4 cm over 30 feet equals 66.767 cm 810 feet it is 4 cm over 30 he equals 108 cm therefore the dimensions on the scale is 66.67 cm X 180
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Marrrta [24]

Answer:

option c

Step-by-step explanation:

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3 0
3 years ago
What is the sum? (2x + 4)/(x + 1) + (- x + 5)/(x + 1) (x - 1)/(x + 1) (1 - 1)/(2x + 2) (x + 9)/(x + 1) (x + 9)/(2x + 2)
butalik [34]

Answer:

Step-by-step explanation:

Since they already have a common denominator of x+1 we can add the numerators

(2x+4-x+5)/(x+1)

(x+9)/(x+1)

4 0
3 years ago
What are the coordinates of the vertices of the image?
Lady bird [3.3K]

Step-by-step explanation:

(2,4)===(4,-2)

(4,3)===(3,-4)

(2,3)===(3,-2)

8 0
2 years ago
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
3 years ago
Find the value of x. If your answer is not an integer express it in simplest radical form.
joja [24]
???????????????????????????????????????????
5 0
4 years ago
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