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You have 55,000 in your savings account that pays 2.5% annual interest and the inflation rate is 3.4%. How much buying power wil

diamong [38]

We solve the question as follows:
Simple interest=Principle×Rate×Time
Thus given:
p=$55000, R=2.5%, time= 1 year
thus
Interest=55000×0.025×1=$1375

To evaluate the amount required to keep up with the inflation, your interest rate should match the inflation rate otherwise prices are going up faster than the savings.
Required interest rate=55000×0.034×1=$1870

The buying power lost will be the difference between your required interest and actual interest.

Thus:
Buying power lost=1870-1375=$495

8 0

3 years ago

What is the possible rational roots for this polynomial 6x³+5x²+10x+3=0

8090 [49]

Answer:

See below.

Step-by-step explanation:

Using the Rational Roots Theorem:

Factors of 3: 1, 3 ( = p).

Factors of 6: 1,2,3,6 ( = q).

Possible real roots are a 1 or 3 from p / q = +/- 1/1, +/- 3/1 , +/-1/2, +/- 1/3 , +/- 1/6, +/- 3/2.

3 0

2 years ago

PLEASE HELP!! 25 POINTS AWARDED

kondaur [170]

Answer:

The following numbers ARE functions:

2, 3, 6, 7, 9, 12

Step-by-step explanation:

A function is only possible if the x values have NO REPEATING NUMBER!!!

Every number that isn't mentioned above has at least 1 number in it's x-values that repeats.

Question 1 has the 8 and 4 with 2 numbers.

Question 4 the 3 repeating. (There are 2 dots over the 3)

Question 5 has numbers 1 and 5 repeating many times

Question 8 numbers 1 and 2 are repeated twice

Question 10 number 3 repeats twice

Question 11 has the 1 repeated

8 0

3 years ago

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a Poisson process at the rate of 5.5 per hour and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$