Answer:
d) ≤
Step-by-step explanation:
Take half of the coefficient of x (which is 2/5) and square it:
[ (1/2)(2/5) ]^2 = (1/5)^2 = 1/25, or 0.04
Thus, to rewrite x^2 + (2/5)x to include a perfect square trinomial,
x^2 + (2/5)x = x^2 + (2/5)x + (1/5)^2 - (1/5)^2, or
(x+1/5)^2 - (1/5)^2, or (x + 1/5)^2 - 1/25
Answer:
Find the hypotenuse:
3^3 + 10^2 = 109
Square root of 109 is around 10.4
(g*f)(0)= (x^3)*(2x+6)
(g*f)(0)= (0^3)*(2(0)+6)
(g*f)(0)= (0)*(0+6)
(g*f)(0)= (0)*(6)
(g*f)(0)= 0
The equation in spherical coordinates will be a constant, as we are describing a spherical shell.
r(φ, θ) = 8 units.
<h3>
How to rewrite the equation in spherical coordinates?</h3>
The equation:
x^2 + y^2 + z^2 = R^2
Defines a sphere of radius R.
Then the equation:
x^2 + y^2 + z^2 = 64
Defines a sphere of radius √64 = 8.
Then we will have that the radius is a constant for any given angle, then we can write r, the radius, as a constant function of θ and φ, the equation will be:
r(φ, θ) = 8 units.
If you want to learn more about spheres, you can read:
brainly.com/question/10171109
