Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2
Answer:
Step-by-step explanation:
We have been given an equation 
. We are asked to solve our given equation.
First of all, we will add 3 to both sides of our equation.
Now, we will divide both sides of our equation by 4.
Upon rounding our answer to nearest thousandth (3 places after decimal) we will get,
Therefore, the solution for our given equation is .
Answer: A
Step-by-step explanation: once you line the numbers up in order from least the greatest, the two middle numbers will be 12. Add 12 + 12 and you get 24. Then divide it by 2 and get 12. That is your median. Your 1st quartile will be 10. Your second quartile will be 15. Your minimum number is 4 and your maximum number is 18.
For a linear function: The graph is a straight line
For a non-linear function: The graph is not a straight line
The given graph is not a straight line and is rather a curve with several turning points i.e several ups and downs. Hence the graph belongs to a Non-Linear Function.
A relation is non-function when it passes through same x value more than once. Since this cannot be observed in the given graph, the graph belongs to a function.
Therefore, the correct answer to this question is "Non-Linear Function"
The answers are as follows:
Box 1) D
Box 2) .02D
Box 3) D + .02D
