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mr Goodwill [35]
3 years ago
6

PLLLLLLLLLLLEEEEEEEEEEEEEEEzzzZZzZzZZZZZzzzzZZZZ HEEEEEEEEEEEEEEEELLLLLLLLLLLPPPPPPPPP ASAP

Mathematics
2 answers:
Elden [556K]3 years ago
6 0

Answer:

there is no question my man

Dimas [21]3 years ago
4 0

Answer:

With what?

Step-by-step explanation:

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What is the sum of entries a32 and b32 in A and B? (matrices)
Katyanochek1 [597]

Answer:

The correct answer is option D.  13

Step-by-step explanation:

From the figure we can see two matrices A and B

<u>To find the sum of a₃₂ and b₃₂</u>

From the given attached figure we get

a₃₂ means that the third row second column element in the matrix A

b₃₂ means that the third row second column element in the matrix B

a₃₂ = 4 and b₃₂ = 9

a₃₂ + b₃₂ = 4 + 9

 = 13

The correct answer is option D.  13

4 0
3 years ago
Read 2 more answers
Use a graphing calculator to find the value of f(x) when x= 3 for each function
MaRussiya [10]
9. f(x)= 1/3x-2
f(3)= 1/3(3)-2
f(3)= 1-2
f(3)= -1
6 0
3 years ago
Help? Multi-Step Equations - Fractions. Solve the Equation.<br>PLEASE DO IT STEP BY STEP (visual)
GREYUIT [131]
R - 10/3 + 1/2 = -11/6...if u multiply everything by the common denominator 6, it will get rid of the fractions.

(6)r - 6(10/3) + 6(1/2) = 6(-11/6)
6r - 60/3 + 6/2 = - 66/6...simplify
6r - 20 + 3 = - 11
6r - 17 = -11
6r = -11 + 17
6r = 6
r = 6/6
r = 1 <===
5 0
3 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
Please help me ASAP please please thank you so much
pickupchik [31]

Answer: a

Step-by-step explanation:

3 0
3 years ago
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