Answer:
In x: 4-1=3
In y: -2
Cartesian coordinates: (3,-2)
Step-by-step explanation:
If we move horizontally we must consider only the x axis, if we move to east it is positive, and if we move to west it is negative.
f we move vertically we must consider only the y axis, if we move to north it is positive, and if we move to south it is negative.
Answer:
-11/10 or -1.1
Step-by-step explanation:
To start, let's get rid of those pesky decimals by multiplying everything by 2. Then we get 9 + 20r = -13. Now, let's isolate the r by subtracting 9 from both sides to get 20r = -22. Finally, we need to divide everything by 20 to get r = -11/10 or -1.1.
If you think about slopes it will always be rise over run! Think of rise as climbing a mountain and run as in walking on the mountain you just climbed. In order to find an equation of any problem, you first need to look at a graph for your first clue. See if the line goes straight through the corners of certain places on the graph. If so than you just count rise over run!
In conclusion my thesis or solution for your question would be C.
We want to know the time, <em>t</em>, it takes the ball to reach a height (<em>y</em>) of 0.

We can factor out the GCF first. The largest number that will divide evenly into 16 and 24 is 8. Also, both terms have a <em>t</em>, so we can factor that out as well:

(-16/8 = -2 and 24/8 = 3)
Using the zero product property, we know that either 8t=0 or -2t+3=0. Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.