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2 years ago

Name

Mathematics

2 answers:

astraxan [27]2 years ago

4 0

Here is your answer
Mark it Magnetic field

LenaWriter [7]2 years ago

3 0

Answer:

1.) -6

2.) 0

3.) 3

4.) -4

Step-by-step explanation:

1.) subract 1 from seven then take the larger numbers sign (-)

2.) 7 - 7 = 0

3.) 5 - 2 = 3

4.) samd step as 1

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Find the missing angle

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

The value of (a–1)+92 - +24,5 " when a= 2 and b=-1

Andre45 [30]

Answer:

256271

Step-by-step explanation:

6165253-6728282-289292

3 0

2 years ago

little melinda has nickels and quarters in her bank she has 8 fewer than nickels she has 5.60 in the bank how many coins of each

Talja [164]

Answer:

She has 20 coins in her bank, where she has 12 nickels and 8 quarters

Step-by-step explanation:

A quarter is 25 cents

A nickel is 5 cents
Since she has 8 fewer than nickels, we add 8 to the number of nickels

Q = N + 8, 25Q + 5N = 560

25(N + 8) + 5N = 560

25N + 200 + 5N = 560

25N + 200 - 200 + 5N = 560 - 200

30N = 360

30N / 30 = 360 / 30

N = 12 nickels

Finding amount of Quarters:

Q = N + 8 → Q = 12 + 8

Q = 20 quarters

Learn more about System of Linear Equations here: brainly.com/question/2226590

6 0

1 year ago

Help can someone help me find the value of ClX Y and Z I would appreciate it luvvs ;) ♡

Stolb23 [73]

$\\ \sf\longmapsto 9x+46=35$

$\\ \sf\longmapsto 9x=35-46$

$\\ \sf\longmapsto 9x=-11$

$\\ \sf\longmapsto x=\dfrac{-11}{9}$

6 0

2 years ago

Motorola used the normal distribution to determine the probability of defects and the number

vovangra [49]

Answer:

a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4

b.p=0.0026,total defects=2.6

c.Less of the items produced will be classified as defects.

Step-by-step explanation:

a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.

$\mu=10,\sigma=0.15\\Therefore:-\\z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.15}\approx-1.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.15}\approx+1.0\\P(x10.15)=P(Z+1.0)\\=2P(Z$

Total defects=Production*Probability

=0.3174*1000

$=317.4$

b. $\mu=10,\sigma=0.05$

therefore:-

$z=\frac{x-\mu}{\sigma}=\frac{9.85-10}{0.05}\approx-3.0\\z=\frac{x-\mu}{\sigma}=\frac{10.15-10}{0.05}\approx+3.0\\\\=P(x10.15)=P(Z+3.0)\\=2P(Z$

Defects=Probability*Production

=0.0026*1000

=2.6

c.Reducing process variation results in a significant reduction in the number of unit defects.

3 0

3 years ago