Answer:
x = 8 and y = 10
Step-by-step explanation:
Since the figures are congruent:
Angle PQR = EFG
6y + x = 68
Segment QR = FG
2x - 4 = 12
Solving that:
2x - 4 = 12
2x = 16
x = 8
Replacing x in 6y + x =68
6y + 8 = 68
6y = 60
y = 10
Answer:
Step-by-step explanation:
What did you include in your response? Check all that apply.
There would be an open circle at (2, 1). <u>Yes</u>
There would be a closed circle at (2, 3). <u>Yes</u>
There would be an open circle at (4, 3). <u>Yes</u>
There would be a closed circle at (4, −4). <u>Yes</u>
Endpoints that are not included in the domain of a particular piece of a function are represented by an open circle. <u>Yes</u>
Answer:
-.6 repeating
Step-by-step explanation:
Answer:
5.4
Step-by-step explanation:
5.2, 5.4, 4.9, 4.4, 5.1
4.4, 4.9, 5.1, 5.2, 5.4
5.4 is the maximum
Hope this helped!
Answer:
12.5 pie , 39.25 using pie=3.14, and 39.28 to be exact
Step-by-step explanation:
BTW n=pie
10in= Diameter
5in=Radius
Area=n5^2
= 25n/2
=12.5n
12.5 times 3.14= 39.25
22/7 times 12.5= 39.2857143
