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Serjik [45]
2 years ago
6

What are Limit of g (x) as x approaches 4 negative and Limit of g (x) as x approaches 4 plus, if they exist?

Mathematics
1 answer:
Novay_Z [31]2 years ago
7 0

Answer:

I can't even see take a closer picture

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A circle cuts the x-axis at (4,0) and (14,0), and cuts the y-axis at (0,6) and (0,8). Find it's equation
gayaneshka [121]
It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
The major (y) radius is 1 and the minor (x) radius is 5
Therefore the equation is (x-9)/5 + (y-7)/1 = 1
5 0
3 years ago
Consider the next 1000 90% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi
Ivenika [448]

Answer:

90% CI expects to capture u 90% of time

(a) This means 0.9 * 1000 = 900 intervals will capture u

(b) Here we treat CI as binomial random variable, having probability 0.9 for success

n = 1000

p = 0.9

For this case, applying normal approximation to binomial, we get:

mean = n*p= 900

variance = n*p*(1-p) = 90

std dev = 9.4868

We want to Find : P(890 <= X <= 910) = P( 889.5 < X < 910.5) (integer continuity correction)

We convert to standard normal form, Z ~ N(0,1) by z1 = (x1 - u )/s

so z1 = (889.5 - 900 )/9.4868 = -1.11

so z2 = (910.5 - 900 )/9.4868 = 1.11

P( 889.5 < X < 910.5) = P(z1 < Z < z2) = P( Z < 1.11) - P(Z < -1.11)

= 0.8665 - 0.1335

= 0.733

6 0
3 years ago
I have two marks more than you do and the sum of both our marks is equal to 14 what are our marks
svet-max [94.6K]

your marks 9 my marks 5

Step-by-step explanation:

1/2 of 14 = 7

7 + 2 = 9

14 - 9 = 5

so your marks are 9 and mine are 5

Hope this helped ..

5 0
2 years ago
Data set X and data set Y both have the same interquartile range. If the first quartile of data set X is less than the first qua
guapka [62]
<span>Data set X and data set Y both have the same interquartile range. If the first quartile of data set X is less than the first quartile of data set Y, then the third quartile of data set X is greater than the third quartile of data set Y.

False</span>
7 0
3 years ago
The diagram shows a square.
tensa zangetsu [6.8K]
The work shown in the box is correct.
8 0
3 years ago
Read 2 more answers
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