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avanturin [10]
3 years ago
13

Enter the values of h and I so that y=x2+6x+10 is in vertex form Y=(x+__)^2+___

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Use\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\y=x^2+6x+10=x^2+2(x)(3)+10=\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2+10\\\\=(x+3)^2-9+10=(x+3)^2+1\\\\Answer:\ \boxed{y=(x+3)^2+1}

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tennis balls with a diameter of 2.5in are sold in cans of three. the can is a cylender. what is the volume of the area not occup
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Answer:

The volume of the area not occupied by the tennis balls is 12.28 cubic inches.

Step-by-step explanation:

It is given that tennis balls with a diameter of 2.5in are sold in cans of three. the can is a cylinder.

Radius of ball = Radius of can = \frac{2.5}{2}=1.25

Height of can = 2.5\times 3=7.5

The volume of sphere is

V=\dfrac{4}{3}\pi r^3

where, r is radius of sphere.

The volume of a tennis balls is

V=\dfrac{4}{3}\pi (1.25)^3

V=8.18123

V\approx 8.18

Volume of three tennis balls is

V_1=3\times 8.18=24.54

The volume of cylinder is

V=\pi r^2h

The volume of can is

V_2=\pi (1.25)^2(7.5)

V_2=36.81553

V_2\approx 36.82

The volume of the area not occupied by the tennis balls is

Volume = Volume of cylinder - Volume of three tennis balls

            = 36.82 - 24.54 = 12.28 inches

Therefore, the volume of the area not occupied by the tennis balls is 12.28 cubic inches.

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Step-by-step explanation:

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