The length of the side of the smaller cube is 3.48cm
- Let the length of the smaller side be x
- The length of the bigger side will be x + 2
- Volume of the smaller cube = x^3
- Volume of the larger cube = (x+2)^3
If their <u>volumes differ by 152 cm^3,</u> then;
x^3 - (x+2)^3 = 153
Expand
x^3 - (x^3 + 3x^2(2^2) + 3x(2^3) + 2^4) = 153
x^3-x^3-12x^2-24x + 16 = 153
-12x^2-24x + 16 = 153
12x^2 + 24x - 16 - 153 = 0
12x^2 + 24 -169 = 0
On factorizing, the value of x is 3.48. This shows that the length of the side of the smaller cube is 3.48cm
Learn more on volume of cubes here: brainly.com/question/1972490
Let a=number of pens and b=number of pencils.
8a+7b=3.37; 5a+11b=3.10.
To eliminate a variable multiply the first eqn by 5 and the second by 8:
40a+35b=16.85, 40a+88b=24.80.
Subtract these equations: 53b=7.95, b=$0.15. So 5a=3.10-1.65=$1.45, a=$0.29.
Pens are $0.29 each and pencils $0.15.
Answer:
answer in the file
Step-by-step explanation:
The work group can be expected to achieve 20 objectives.
25 x 0.80 = 20
