an object is traveling at a steady speed of 10 1/5 km/h. how long will it take the object to travel 4 4/5

Mathematics

1 answer:

zaharov [31]3 years ago

6 0

Incomplete question but the comnplete question is how long will it take the object to travel 4 4/5km

Answer: time taken for the object to travel = 0.47 hrs

Step-by-step explanation:

Step 1 -- The formulae to represent the relationship of speed, distance and time .

Speed = Distance / Time

Where Speed = 10 1/5 km/h

Distance = 4 4/5 km

Step 2 --- Solving

Time = Distance / Speed

= 4 4/5 km / 10 1/5 km/h

= 24/ 5 x 5/ 51 = 24/51 =0.47 hrs

4. 8 / 10.2 = 0.47 hrs

Therefore the time taken for the object to travel = 0.47 hrs

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Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$