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Aleonysh [2.5K]
2 years ago
8

HELP DUE IN 10 MINUTES!!

Mathematics
2 answers:
gulaghasi [49]2 years ago
7 0

\\ \rm\longmapsto y-6=4(x+5)

  • Convert to y=mx+c

\\ \rm\longmapsto y-6=4x+20

\\ \rm\longmapsto y=4x+20+6

\\ \rm\longmapsto y=4x+26

  • c is y intercept
  • m is x intercept

y intercept=26

x intercept=4

Pavlova-9 [17]2 years ago
3 0

Answer:

x intercept = 26

y intercept = 6.5

Step-by-step explanation:

n/a

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Let v1,....., vk be vectors, and suppose that a point mass of m1,....., mk is located at the tip of each vector. The center of m
a_sh-v [17]

Answer: m1 = 4

m2 = 5

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Step-by-step explanation:

given (21/11, 6/11) = m1 (-1/3) + m2 (3, -2) + m3 (5, 2)

= (-m1 + 3m2 + 5m3) / 11 = 21/11

= (3m1 + (-2)m2 + 2m3) / 11 = 6/11

so that m1 + m2 +m3 = 11

-m1 + 3m2 + 5m3 = 21

3m1 - 2m2 + 2m3 = 6

from this, we get the augmented matrix as

\left[\begin{array}{cccc}-1&1&1&11\\-1&3&5&21\\3&-2&2&6\end{array}\right]

= \left[\begin{array{cccc}-1&1&1&11\\0&4&6&32\\0&-5&-1&-27\end{array}\right]  \left \{ {{R2=R2 + R1} \atop {R3=R3 -3R1 }]} \right.

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&-5&-1&-27\end{array}\right]

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&0&13/2&13\end{array}\right]

(R3 = R3 + 5R2)

this gives m1 + m2 + m3 = 11

m2 + 3/2 m3 = 8

13/2 m3 = 8

13/2 m3 = 13

m3 = 2

m2 = 8 -3/2 (2) = 5

= m1 = 11- 5 - 2 = 4

this gives

m1 = 4

m2 = 5

m3 = 2

4 0
3 years ago
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Answer:

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Step-by-step explanation:

i have got $ 12.4

5 0
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Read 2 more answers
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irga5000 [103]

Answer:

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Step-by-step explanation:

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8 0
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