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hram777 [196]
4 years ago
8

Sara can run 49 yards in 7 seconds. At that rate, how many feet can she run in 3 minutes?

Mathematics
2 answers:
Finger [1]4 years ago
8 0

Answer:

Distance ran by Sara in 3 minutes is 3780 feet.

Step-by-step explanation:

We know that,

1 yard = 3 feet

So, 49 yards = 49 × 3 feet = 147 feet

Now, it is given that Sara can run 49 yards in 7 seconds. So, we can say that, Sara can run 147 feet in 7 seconds

So, distance ran by Sara in 7 seconds = 49 yards = 147 feet

Now, distance ran by Sara in 1 second = (147 ÷ 7) feet = 21 feet

Now, 1 min = 60 sec, then 3 min = 3 × 60 sec = 180 sec

So, distance ran by Sara in 3 min or 180 sec = 21 × 180 = 3780 feet

∴ distance ran by Sara in 3 minutes is 3780 feet.

weeeeeb [17]4 years ago
7 0

Answer:

3780 feet

Step-by-step explanation:

49/7*60*3(be careful that it is 3 minutes,not seconds)

=1260

Now,we have to convert yards into feet.

1260 yards = 3780 feet

Because feet is three times yard.

Hope this answer helps! ;)

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Answer:

Step-by-step explanation:

Use DESMOS to make the graph.  You can either rearrange the equation to put it in the form y = mx + b, or leave it as written.  The attached graph, has bot, and they overlap.

y+4=2/5(x−3)

or

y = (2/5)x-5.2

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3 years ago
A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki
shepuryov [24]

Answer

given,

mean = 12 Kg

standard deviation = 0.5 Kg

assume the observed statistic is = 11.1

 now, \bar{X}=11.1 , \mu = 12 , \sigma = 0.5

assuming the number of sample = 4

n = 4

Hypothesis test:

H₀ : μ≥ 12

Ha : μ < 12

now,

significant level α = 0.05

z* = \dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z* = \dfrac{11.1-12}{\dfrac{0.5}{\sqrt{4}}}

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Test statistics, Z* = -3.60

P-value

P(Z<-3.60) = 0.002 (from z- table)

P- value = 0.002

now,

reject the value of H₀ when P-value < α

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since, it is less P-value < α , we have to reject the null hypothesis

5 0
3 years ago
I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

solving for y, we have

\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

4 0
1 year ago
In a choir there are 27 men and 60 women.
guapka [62]

Answer:

b) A person is chosen at random from the choir.

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scoray [572]

Answer:

D

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6 0
3 years ago
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